BITSAT 2013 Question Paper with Answers


BITSAT 2013 Question Paper with Answers: BITSAT is computer based online test for admissions to Integrated First Degree programs of BITS, Pilani at Pilani campus, KK Birla Goa campus and Hyderabad campus. Here we are providing the last previous years question papers for BITSAT Examination with their answers. With the help of these BITSAT Question Papers, candidates can estimate the level of entrance examination organized by Birla Institute of Technology and Science (BITS) for admission into Integrated First Degree programs. One can check the BITSAT 2013 Question Paper with Answers here.

BITSAT 2013 Question Paper with Answers

Candidates who are willing to appear for the BITSAT Exam must check the previous years question papers for better understanding of the exam pattern. By practicing previous year question papers candidates will be able to know their weak areas and then can make their study plan accordingly. BITSAT 2013 Question Papers with Answers is given here for candidate’s reference.

BITSAT 2013 Question Paper


1. If α, β are the roots of ax2 + bx + c = 0 then (-1/α), (-1/β) are the roots of

(a) ax2 – bx + c = 0
(b) cx2 – bx + a = 0
(c) cx2 + bx + a = 0
(d) ax2 – bx – c = 0

2. The number of real roots of the equation

(x – 1)2 + (x – 2)2 + (x – 3)2 = 0 is

(a) 1
(b) 2
(c) 3
(d) None of these

3. If S is the set containing values ​​of x satisfying [x]2 – 5[x] + 6 0 , where [x] denotes GIF then S contains

(a) (2, 4)
(b) (2, 4]
(c) [2, 3]

4. Seven people are seated in a circle. How many relative arrangements are possible?

(a) 7!
(b) 6!
(c) 7P6
(d) 7C6

5. In how many ways can 4 people be seated on a square table, one on each side?

(a) 4!
(b) 3!
(c) 1
(d) None of these

6. Four different items have to be placed in three different boxes. In how many ways can it be done such that any box can have any number of items?

(a) 34
(b) 43
(c) 4P3
(d) 4C3

7. What is the probability that, if a number is randomly chosen from any 31 consecutive natural numbers, it is divisible by 5?

(a) (6/31)
(b) (7/31)
(c) (6/31) or (7/31)
(d) None of these

8. The mean of a binomial distribution is 5, then its variance has to be

(a) > 5
(b) = 5
(c) < 5
(d) = 25

9. If a is the single AM ​​between two numbers a and b and S is the sum of n AM ‘s between them, then S/A depends upon

(a) n, a, b
(b) n, a
(c) n, b
(d) n

1021/4 41/8 81/16 161/32 .. upto equal to

(a) 1
(b) 2
(c) 3/2
(d) 5/2

11. The odds in favor of India winning any cricket match is 2 : 3. What is the probability that if India plays 5 matches, it wins exactly 3 of them?

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